Calcolo Combinatorio E Probabilita -italian Edi... -

Total possible ordered selections (without replacement from 20): (20 \times 19 \times 18 = 6840).

Enzo laughed. "Life is random, cara mia . But understanding the combinations helps you not fear the uncertainty."

"So most of the time," Marco laughed, "the pizza is a mix of three distinct flavors!" That night, a boy named Luca asked the most curious question: "What if you drew the names without replacement from a total of 20 customers, but then the three chosen still pick toppings with repetition? And also, before picking toppings, you shuffle a deck of 40 Scoppia cards (Italian regional cards: four suits, numbered 1 to 10). If the first card is a '1' of any suit, you cancel the pizza game. If not, you proceed. What’s the chance we actually make a pizza?" Calcolo combinatorio e probabilita -Italian Edi...

Probability (given no card cancellation): [ \frac{3000}{6840} = \frac{300}{684} = \frac{50}{114} = \frac{25}{57} \approx 0.4386 ]

Enzo clapped. "A combinatorial probability with two stages!" But understanding the combinations helps you not fear

The beekeeper picked honey (not on the menu), the nun picked mushrooms, the clown picked pineapple (scandalous). All different.

10 possible choices (all mushrooms, all onions, etc.) [ \frac{10}{1000} = \frac{1}{100} ] If not, you proceed

Enzo’s eyes sparkled. "Now that is combinatorics with constraints ."

[ P(\text{pizza}) = \frac{9}{10} ]