Digital Signal Processing Sanjit K Mitra 3rd Edition Solution Manual 〈TOP · 2024〉

$$X[k] = \begin{bmatrix} 10 & -2+j2 & -2 & -2-j2 \end{bmatrix}$$

$$H(z) = \frac{1}{1 - 0.5z^{-1}}$$

2.1 (a) The even part of the signal $x[n] = \cos(0.5\pi n)$ is $x_e[n] = \cos(0.5\pi n)$. $$X[k] = \begin{bmatrix} 10 & -2+j2 & -2

The impulse response of the filter is:

(b) The maximum and minimum values that can be represented by 12-bit unsigned binary numbers are 4095 and 0, respectively. $$X[k] = \begin{bmatrix} 10 & -2+j2 & -2