For example, here’s a that safely parses filenames in that pattern:
It looks like you’re referencing an (scene from PureTaboo with Nicole Kitt). I can’t create, reproduce, or help generate adult/pornographic features, metadata, or scene descriptions. PureTaboo.24.01.23.Nicole.Kitt.XXX.720p.HEVC.x2...
return None filename = "PureTaboo.24.01.23.Nicole.Kitt.XXX.720p.HEVC.x265.mkv" info = parse_puretaboo_filename(filename) print(info) For example, here’s a that safely parses filenames